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pasha4431
pasha4431
19.03.2023 15:31 •  Химия

H3PO4 (aq) + 3 KOH (aq) → 3 H2O (l) + K3PO4 (aq)
СКАЖИТЕ СКОЛЬКО В ЭТОМ УРАВНЕНИИ КОЕФИЦИЕНОВ!?

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Ответ:
BTS48
BTS48
22.09.2021 12:24

Дур*

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Must Waste More Time...

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Ответ:
ValeriaChernysheva
ValeriaChernysheva
02.04.2023 05:47

CIVII20II7

Объяснение:

определим валентность хлора в его соединении с кислородом — Cl2O7.

 

1. Записываем известную валентность кислорода над формулой. Неизвестную валентность обозначаем буквой x:

 

Clx2OII7.

 

2. Находим сумму единиц валентности каждого элемента. Для этого его валентность умножаем на число атомов:

 

x⋅2=2⋅7.

 

3. Вычисляем x:

 

2x=14,x=14:2=7.

 

Валентность хлора равна VII:

 

ClVII2OII7.

Составление формулы бинарного соединения по валентностям химических элементов

Если известны валентности двух элементов, то можно составить формулу их соединения.

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