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Відповідь:
11,2л N2 і H2 містять одинакову кількість молекул(в одинакових обємах газі міститься одинакова кількість молекул)
28г N2 і 1г Н2
M(N2)=28г/моль
M(H2)=2г/моль
n(N2)=28/28=1
n(H2) -1/2=0,5моль
N(N2)=6.02*10²³*1=6.02*10²³моль⁻¹
N(H2)=6.02*10²³*0,5=3.01*10²³моль⁻¹
один моль N2 містить більше молекул, ніж 0,5 моль Н2
5,6л O2 71г CI2
M(CI2)=71г/моль
n(O2)=5,6/22,4=0,25моль
n(CI2)=71/71=1моль
N(CI2)=6.02*10²³*1=6.02*10²³моль⁻¹
N(O2)=6.02*10²³*0,25=1,505*10²³иоль⁻¹
один моль СІ2 містить більше молекул, ніж 0,25 моль О2
Пояснення:
Чтобы найти массу сероводорода, для начала нужно найти его кол-во ( n)
1) n(H2S) = 67,2 л : 22,4 л/моль = 3 моль
Теперь, зная количество,мы можем найти массу, но для этого сперва найдем молярную массу сероводорода
2) M(H2S)= 1*2+32=34г/моль
Масса равна произведению количества вещества и его молярной массы
3)m(H2S)=3 моль * 34 г/моль = 102 г
теперь найдем массу раствора
4)m р-ра (H2S)= 102 г+200 г =302 г
теперь мы можем найти концентрацию раствора:
5) w(H2S) =102г : 302г * 100% = 33,77%
ответ: w(H2S) = 33,77%