m(р-ра) = 146 g
W(HCl) = 10%
V(CO2) - ?
m(HCl) = 0.1 * 146 = 14.6 g
n(HCl) = 14.6 / 36.5 = 0.4 mol
0.4 mol x mol
Na2CO3 + 2HCl → 2NaCl + CO2 + H2O
2 mol 1 mol
2:0.4 = 1:x
2x = 0.4
x = 0.2
V(CO2) = 0.2 * 22.4 = 4.48 l
ответ: V(CO2) = 4.48 l.
m(р-ра) = 146 g
W(HCl) = 10%
V(CO2) - ?
m(HCl) = 0.1 * 146 = 14.6 g
n(HCl) = 14.6 / 36.5 = 0.4 mol
0.4 mol x mol
Na2CO3 + 2HCl → 2NaCl + CO2 + H2O
2 mol 1 mol
2:0.4 = 1:x
2x = 0.4
x = 0.2
V(CO2) = 0.2 * 22.4 = 4.48 l
ответ: V(CO2) = 4.48 l.