дано
m(H3PO4) = 9.8 g
m(Ca3(PO4)2) = 15 g
η(Ca3(PO4)2)-?
2H3PO4+3Ca(OH)2-->Ca3(PO4)2+6H2O
M(H3PO4) = 98 g/mol
n(H3PO4) = m/M = 9.8 / 98 = 0.1 mol
2n(H3PO4) = n(Ca3(PO4)2)
n(Ca3(PO4)2) = 0.1 / 2 = 0.05 mol
M(Ca3(PO4)2) = 310 g/mol
m теор (Ca3(PO4)2) = n*M = 0.05 * 310 = 15.5 g
η(Ca3(PO4)2) = mпрак (Ca3(PO4)2) / m теор (Ca3(PO4)2) * 100%
η(Ca3(PO4)2) = 15 / 15.5 * 100% = 96.77%
ответ 96.77%
Объяснение:
дано
m(H3PO4) = 9.8 g
m(Ca3(PO4)2) = 15 g
η(Ca3(PO4)2)-?
2H3PO4+3Ca(OH)2-->Ca3(PO4)2+6H2O
M(H3PO4) = 98 g/mol
n(H3PO4) = m/M = 9.8 / 98 = 0.1 mol
2n(H3PO4) = n(Ca3(PO4)2)
n(Ca3(PO4)2) = 0.1 / 2 = 0.05 mol
M(Ca3(PO4)2) = 310 g/mol
m теор (Ca3(PO4)2) = n*M = 0.05 * 310 = 15.5 g
η(Ca3(PO4)2) = mпрак (Ca3(PO4)2) / m теор (Ca3(PO4)2) * 100%
η(Ca3(PO4)2) = 15 / 15.5 * 100% = 96.77%
ответ 96.77%
Объяснение: