дано
V(H2) = 20L
m(Zn)-?
Zn+2HCL-->ZnCL2 + H2
Vm = 22.4 L/mol
M(Zn) = 65 g/mol
m(Zn) = M(Zn) * V(H2) / Vm = 65 * 20 / 22.4 = 58 g
ответ 58 г
дано
V(H2) = 20L
m(Zn)-?
Zn+2HCL-->ZnCL2 + H2
Vm = 22.4 L/mol
M(Zn) = 65 g/mol
m(Zn) = M(Zn) * V(H2) / Vm = 65 * 20 / 22.4 = 58 g
ответ 58 г