3NaOH+AlCl3=Al(OH)3+3NaCl
m(NaOH)=120*0.1=12г
v(AlCl3)=v(NaOH)/3=12/40/3=0.1 моль
m(Al(OH)3)=0.1*78=7.8г
3NaOH+AlCl3=Al(OH)3+3NaCl
m(NaOH)=120*0.1=12г
v(AlCl3)=v(NaOH)/3=12/40/3=0.1 моль
m(Al(OH)3)=0.1*78=7.8г