Mr(Ba(OH)2) = 137 + 16*2 + 1*2 = 171
W(Ba) = Ar(Ba) *n / Mr(Ba(OH)2) *100% = 137 1/171 *100% = 80%
W(O) =Ar(O) *n / Mr(Ba(OH)2)*100% =
16*2/171 *100% = 19%
W(H) = Ar(H) *n / Mr(Ba(OH)2) *100% = 1*2/171 *100% =1%
Mr(Ba(OH)2) = 137 + 16*2 + 1*2 = 171
W(Ba) = Ar(Ba) *n / Mr(Ba(OH)2) *100% = 137 1/171 *100% = 80%
W(O) =Ar(O) *n / Mr(Ba(OH)2)*100% =
16*2/171 *100% = 19%
W(H) = Ar(H) *n / Mr(Ba(OH)2) *100% = 1*2/171 *100% =1%