V(C2H5Cl) = 22.4 l N(C2H5Cl) = 22.4 / 22.4 = 1 mol
V(Cl) - ?
x mol 1 mol
2C2H5 + Cl2 → 2C2H5Cl
1 mol 2 mol
1:x = 2:1
2x = 1
x = 0.5
V(Cl) = 0.5*22.4 = 11.2 l
V(C2H5Cl) = 22.4 l N(C2H5Cl) = 22.4 / 22.4 = 1 mol
V(Cl) - ?
x mol 1 mol
2C2H5 + Cl2 → 2C2H5Cl
1 mol 2 mol
1:x = 2:1
2x = 1
x = 0.5
V(Cl) = 0.5*22.4 = 11.2 l