2CH3COOH+Mg=(CH3COO)2Mg+H2n(CH3COOH)=11.2/60=0.186моль2к1n(H2)=0.186/2=0.093мольV(H2)=0.093*22.4=2.0832=2литра
2CH3COOH+Mg=(CH3COO)2Mg+H2
n(CH3COOH)=11.2/60=0.186моль
2к1
n(H2)=0.186/2=0.093моль
V(H2)=0.093*22.4=2.0832=2литра