BaO+H2O=Ba(OH)2
n(Ba)=382,5/153=2,5; n(Ba(OH)2)=2,5; m(Ba(OH)2)=2,5*171=427,5;
W(Ba(OH)2)=427,5/(382,5+400)=0,5463(54,63%).
BaO+H2O=Ba(OH)2
n(Ba)=382,5/153=2,5; n(Ba(OH)2)=2,5; m(Ba(OH)2)=2,5*171=427,5;
W(Ba(OH)2)=427,5/(382,5+400)=0,5463(54,63%).