2Al+3H2SO4=Al2(SO4)3+3H2
m(Al)=20*(1-0.05)=19г
n(Al)=19/27=0.7моль
n(H2)=3/2*n(Al)=1.5*0.7=1.06моль
V(H2)=1.06*22.4=23.6 Литра
2Al+3H2SO4=Al2(SO4)3+3H2
m(Al)=20*(1-0.05)=19г
n(Al)=19/27=0.7моль
n(H2)=3/2*n(Al)=1.5*0.7=1.06моль
V(H2)=1.06*22.4=23.6 Литра