BaCl2+H2SO4=BaSO4⬇️+2HCl
m(H2SO4)=(150г×15%)/100%=22,5г
n(H2SO4)=22,5/98=0,23моль
n(H2SO4)=n(BaSO4)
m(BaSO4)=0,23×233=51,29г
BaCl2+H2SO4=BaSO4⬇️+2HCl
m(H2SO4)=(150г×15%)/100%=22,5г
n(H2SO4)=22,5/98=0,23моль
n(H2SO4)=n(BaSO4)
m(BaSO4)=0,23×233=51,29г