дано
m(Fe) = 5.6 g
V(H2)-?
Fe+2HCL-->FeCL2+H2
M(Fe) = 56 g/mol
n(Fe) = m/M = 5.6 / 56 = 0.1 mol
n(Fe) = n(H2) = 0.1 mol
V(H2) = n(H2) * Vm = 0.1 * 22.4 = 2.24 L
ответ 2.24 л
дано
m(Fe) = 5.6 g
V(H2)-?
Fe+2HCL-->FeCL2+H2
M(Fe) = 56 g/mol
n(Fe) = m/M = 5.6 / 56 = 0.1 mol
n(Fe) = n(H2) = 0.1 mol
V(H2) = n(H2) * Vm = 0.1 * 22.4 = 2.24 L
ответ 2.24 л