дано
m(CnH2n+1OH) = 3.7 g
V(H2) = 0.56 L
M(CnH2n+1OH) - ?
M(CnH2n+1OH) = (14n+18) g/mol
2CnH2n+1OH + 2Na-->2CnH2n+1ONa+H2
m(CnH2n+1OH) V(H2)
=
2* M(CnH2n+1OH) Vm
3.7 0.56
2*(14n+18) 22.4
0.56*2*(14n+18) = 3.7*22.4
15.68 n + 20.16 = 82.88
n = 4
2C4H9OH+2Na-->2C4H9ONa+H2
M(C4H9OH) = 12*4+1*9+16+1 = 74 g/mol
ответ 74 г/моль
Объяснение:
дано
m(CnH2n+1OH) = 3.7 g
V(H2) = 0.56 L
M(CnH2n+1OH) - ?
M(CnH2n+1OH) = (14n+18) g/mol
2CnH2n+1OH + 2Na-->2CnH2n+1ONa+H2
m(CnH2n+1OH) V(H2)
=
2* M(CnH2n+1OH) Vm
3.7 0.56
=
2*(14n+18) 22.4
0.56*2*(14n+18) = 3.7*22.4
15.68 n + 20.16 = 82.88
n = 4
2C4H9OH+2Na-->2C4H9ONa+H2
M(C4H9OH) = 12*4+1*9+16+1 = 74 g/mol
ответ 74 г/моль
Объяснение: