W-массовая доля
W=Ar*m/Mr *100%
W(Fe)=56*2/160=0.7*100%= 70%
W(O)=16*3/160=0.3*100%=30%
W(H)=1*2/98=0.02*100%=2%
W(S)=32*1/98=0.33*100%=33%
W(O)=16*4/98=0.65*100%=65%
W-массовая доля
W=Ar*m/Mr *100%
Fe2O3W(Fe)=56*2/160=0.7*100%= 70%
W(O)=16*3/160=0.3*100%=30%
H2SO4W(H)=1*2/98=0.02*100%=2%
W(S)=32*1/98=0.33*100%=33%
W(O)=16*4/98=0.65*100%=65%