Al2(SO4)3 + 3BaCl2 = 3BaSO4(осадок) + 2AlCl3 m(BaCl2) = 0.894*0.25 = 0.22 грn(BaCl2) = 0.22/208 = 0.001 моль = n(BaSO4) m(BaSO4) = 0.001* 233= 0.233 гр
Al2(SO4)3 + 3BaCl2 = 3BaSO4(осадок) + 2AlCl3
m(BaCl2) = 0.894*0.25 = 0.22 гр
n(BaCl2) = 0.22/208 = 0.001 моль = n(BaSO4)
m(BaSO4) = 0.001* 233= 0.233 гр