m(C3H8) = 4.4 g
V(CO2) - ?
n(C3H8) = 4.4 / 44 = 0.1 mol
0.1 mol x mol
C3H8 + 5O2 = 3CO2 + 4H2O
1 mol 3 mol
1:0.1 = 3:x
x = 0.3
V(CO2) = 0.3 * 22.4 = 6.72 l
m(C3H8) = 4.4 g
V(CO2) - ?
n(C3H8) = 4.4 / 44 = 0.1 mol
0.1 mol x mol
C3H8 + 5O2 = 3CO2 + 4H2O
1 mol 3 mol
1:0.1 = 3:x
x = 0.3
V(CO2) = 0.3 * 22.4 = 6.72 l