дано
m(H2S) = 14 g
V(H2)-?
H2+S-->H2S
M(H2S) = 34 g/mol
n(H2S) = m/M = 14 / 34 = 0.41 mol
n(H2) = n(H2S) = 0.41 mol
V(H2) = n*Vm = 0.41 * 22.4 = 9,184 L
ответ 9.184 л
Объяснение:
дано
m(H2S) = 14 g
V(H2)-?
H2+S-->H2S
M(H2S) = 34 g/mol
n(H2S) = m/M = 14 / 34 = 0.41 mol
n(H2) = n(H2S) = 0.41 mol
V(H2) = n*Vm = 0.41 * 22.4 = 9,184 L
ответ 9.184 л
Объяснение: