дано
m(Al) = 54 g
V(H2) -?
2Al+3H2SO4-->Al2(SO4)3+3H2
M(Al) = 27 g/mol
n(Al) = m/M = 54 / 27 = 2 mol
2n(AL) = 3n(H2)
n(H2) = 2*3 / 2 = 3 mol
V(H2) = n*Vm = 3*22.4 = 67.2 L
ответ 67.2 л
Объяснение:
дано
m(Al) = 54 g
V(H2) -?
2Al+3H2SO4-->Al2(SO4)3+3H2
M(Al) = 27 g/mol
n(Al) = m/M = 54 / 27 = 2 mol
2n(AL) = 3n(H2)
n(H2) = 2*3 / 2 = 3 mol
V(H2) = n*Vm = 3*22.4 = 67.2 L
ответ 67.2 л
Объяснение: