BaCl2+H2SO4=BaSO4+2HCl
1) n(BaSO4)=n(H2SO4)=0.2
2) m(H2SO4)=M(H2SO4)*n(H2SO4)=98*0.2=19.6
3)m(раствора)=m(H2SO4)/w(H2SO4)=19.6/0.2=98
BaCl2+H2SO4=BaSO4+2HCl
1) n(BaSO4)=n(H2SO4)=0.2
2) m(H2SO4)=M(H2SO4)*n(H2SO4)=98*0.2=19.6
3)m(раствора)=m(H2SO4)/w(H2SO4)=19.6/0.2=98