дано
m(NaCL) = 15g
m(H2O) = 450 g
W(NaCL)-?
m(ppa NaCL) = m(NaCL) + m(H2O) = 15+450 = 465 g
W(NACL) = m(NaCL) / m(ppa NaCL) *100% = 15 / 465 * 100% = 3.23%
ответ 3.23%
дано
m(NaCL) = 15g
m(H2O) = 450 g
W(NaCL)-?
m(ppa NaCL) = m(NaCL) + m(H2O) = 15+450 = 465 g
W(NACL) = m(NaCL) / m(ppa NaCL) *100% = 15 / 465 * 100% = 3.23%
ответ 3.23%