дано
m(NaOH) = 120 g
+H2SO4
m(H2O)-?
120 X
2NaOH+H2SO4-->Na2SO4+H2O M(NaOH) = 40 g/mol M(H2O) = 18 g/mol
2*40 18
X = 120 * 18 / 2*40 = 27 g
ответ 27 г
дано
m(NaOH) = 120 g
+H2SO4
m(H2O)-?
120 X
2NaOH+H2SO4-->Na2SO4+H2O M(NaOH) = 40 g/mol M(H2O) = 18 g/mol
2*40 18
X = 120 * 18 / 2*40 = 27 g
ответ 27 г