дано
m(Ca3(PO4)2) = 15.5 g
m(P) - ?
4P + 5O2-->2P2O5
3CaO+2P2O5-->Ca3(PO4)2
M(Ca3(PO4)2) = 310 g/mol
n(Ca3(PO4)2) = m/M = 15.5 / 310 = 0.05 mol
4n(P) = n(Ca3(PO4)2)
n(P) = 4*0.05 = 0.2 mol
M(P) = 31 g/mol
m(P) = n*M = 0.2 * 31 = 6.2 g
ответ 6.2 г
Объяснение:
дано
m(Ca3(PO4)2) = 15.5 g
m(P) - ?
4P + 5O2-->2P2O5
3CaO+2P2O5-->Ca3(PO4)2
M(Ca3(PO4)2) = 310 g/mol
n(Ca3(PO4)2) = m/M = 15.5 / 310 = 0.05 mol
4n(P) = n(Ca3(PO4)2)
n(P) = 4*0.05 = 0.2 mol
M(P) = 31 g/mol
m(P) = n*M = 0.2 * 31 = 6.2 g
ответ 6.2 г
Объяснение: