Як з метану можна добути оцтовий ефір?

Дано:                        Решение:

m(Li)=3 г                 3 г                                                       Х г

Найти:                    2 Li     +   2  H2O     =     2LiOH      +    H2

m(H2)=?                 n = 2 моль                                           n = 1 моль

                              М = 7 г/моль                                       М = 2 г/моль

                              m = 14 г                                               m = 2 г

                           3 г Li      -      Х г Н2

                        14 г Li      -     2 г Н2

                        m(H2) = 3*2 / 14 = 0,43 г

          Х г                                                                                            5,6 л

     2СН3-СН2 -СН2-ОН     +    2Na   ->    2CH3-CH2-CH2ONa   +   H2

  n = 1 моль                                                                                     n = 1 моль

 М = 60 г/моль                                                                               Vm = 22,4 л/моль

m = 60 г                                                                                           V = 22,4 л

Х г С3Н8О      -     5,6 л Н2

60 г С3Н8О   -     22,4 л Н2

m(C3H8O) = 5,6 * 60 / 22,4 = 15 г