Mg + 2HCl → MgCl2 + H2
240 / 24 = X / 22,4
X = 240 × 22,4 / 24 = 224 л
224 л – 100%
Y – 70%
Y = 224 × 70 / 100 = 156,8 л
Mg + 2HCl → MgCl2 + H2
240 / 24 = X / 22,4
X = 240 × 22,4 / 24 = 224 л
224 л – 100%
Y – 70%
Y = 224 × 70 / 100 = 156,8 л