Запишите огрегатное состояние не однородных веществ​

                                                                      12,6 г              Х г
Дано:                                          Fe2O3   +  6 HNO3  =  2Fe(NO3)3  +  3H2O

m(HNO3) = 12,6 г                                   n = 6 моль         n = 2 моль

Найти:                                                М = 63 г/моль        М = 194 г/моль

m (Fe(NO3)3) =?                               m = 378 г               m = 388 г

                                                   12,6 г HNO3    -    Х г Fe(NO3)3

                                                    378 г HNO3   -    388 г Fe(NO3)3

                                                    m(Fe(NO3)3) = 12,6 * 388 / 378 = 13 г

1:
2CH4--[t=1500]-->C2H2+3H2
3C2H2--[Cакт.]-->C6H6
C6H6+CH3Cl--[AlCl3/t]-->C6H5CH3+HCl
C6H5CH3--[O]-->C6H5COOH
2:
CaC2+2H2O--->Ca(OH)2+C2H2
3C2H2--[Cакт.]-->C6H6
C6H6+CH3Cl--[AlCl3/t]-->C6H5CH3+HCl
3:
2CH4--[t=1500]-->C2H2+3H2
С2H2+2H2--[Ni]-->C2H6
C2H6+Cl2--[hv]-->C2H5Cl+HCl
C2H5Cl+2Na+CH3Cl--->2NaCl+C3H8
C3H8+Cl2--[hv]-->C3H7Cl+HCl
C3H7Cl+Cl2--[hv]-->C3H6Cl2+HCl
C3H6Cl2+Cl2--[hv]-->C3H5Cl3+HCl
C3H5Cl3+3KOH--->CH2OH-CHOH-CH2OH+3KCl
CH2-OH
I
CH-OH +3C17H35COOH >
I
CH2-OH

---> CH2-O-CO-C17H35
I
CH-O-CO-C17H35 + 3H2O
I
CH2-O-CO-C17H35
4:
CaCO3--[t]-->CaO+CO2
6CO2+6H2O--[hv]-->C6H12O6+6O2
C6H12O6--[дрожжи]-->2C2H5OH+2CO2
C2H5OH+C2H5OH--->C2H5-O-C2H5+H2O
5:
2C4H10+5O2--[солт Mn/t]-->4CH3COOH+2H2O
CH3COOH+Cl2--[Pкр]-->CH2ClCOOH+HCl
CH2ClCOOH+2NH3--->NH2-CH2-COOH+NH4Cl