1) 0,5(2-1,7х)=0,4(2,5-1,1х) 2)5,4(0,5х+4)=8,1(4+х) - вопрос №10521704251125405481433212073154023415828597 от mishutka144qwerty 13.03.2021 11:40

Question

Математика: 1) 0,5(2-1,7х)=0,4(2,5-1,1х) 2)5,4(0,5х+4)=8,1(4+х) 3)3,2(1-2х)=0,7(3х-1,5) 4)0,2(3х-4)=1,6(х-2)

mishutka144qwerty · Answer

1) 0,5(2 - 1,7х) = 0,4(2,5 - 1,1х)1 - 0,85х = 1 - 0,44х- 0,85х + 0,44х = 1 - 10,41х = 0х = 0 : 0,41х = 02) 5,4(0,5х + 4) = 8,1(4 + х)2,7х + 21,6 = 32,4 + 8,1х2,7х - 8,1х = 32,4 - 21,6- 5,4х = 10,8х = 10,8 : (-5,4)х = - 23) 3,2(1 - 2х) = 0,7(3х - 1,5)3,2 - 6,4х = 2,1х - 1,05- 6,4х - 2,1х = - 1,05 - 3,2- 8,5х = - 4,25х = - 4,25 : (- 8,5)х = 0,54) 0,2(3х - 4) = 1,6(х - 2)0,6х - 0,8 = 1,6х - 3,20,6х - 1,6х = - 3,2 + 0,8- х = - 2,4х = 2,4...