1) 2×(х+1)-1/2×(9-х)=1/5×(3х+10)+8; 2)1/2(1/2у-5/7)=3 - вопрос №12112915310821212573121125103619 от maks694 01.09.2020 06:51

Question

Математика: 1) 2×(х+1)-1/2×(9-х)=1/5×(3х+10)+8; 2)1/2(1/2у-5/7)=3 1/2у+1 1/2; зарание

maks694 · Answer

а) 2х+2- 9/2 +1/2х=3/5х+2+82 1/2х-3/5х=2+8-2+9/219/10 х= 12 1/2х= 25/2 ÷ 19/10= 25/2 × 10/19= 125/19=6 11/19х=6 11/19б)1/4у-5/14=3 1/2у+1 1/21/4у-3 1/2у=1 1/2+5/14-3 1/4у=1 12/14=1 6/7у= 1 6/7÷(-3 1/4)у= 13/7×(-13/4)=-169/28=-6 1/28...