1)5(2у-9)+6у=4(3у-2)-21; 2)5у+7(3-у)=3(5-2у)-6; - вопрос №1529643221257335263743523492216575 от реа200 13.03.2020 10:01

Question

Математика: 1)5(2у-9)+6у=4(3у-2)-21; 2)5у+7(3-у)=3(5-2у)-6; 3)7у-4(3у+5)=2-3(4у-9);

реа200 · Answer

1) 5(2у-9)+6у=4(3у-2)-2110у-45+6у= 12у-8-2116у-45=12у-2916у-12у= 45-294у= 16у= 16:4у= 42)5у+7(3-у)=3(5-2у)-65у+21-7у=15-6у-6-2у+21=9-6у6у-2у=9-214у= -12у= -12:4у=-33)7у-4(3у+5)=2-3(4у-9)7у-12у-20= 2-12у+27-5у-20= 29-12у12у-5у= 20+297у= 49у= 49:7у= 7...