1)f(x)= x^5 -1/x^2, x0=-1 2) y = 5x^7-(4/x)+(1/x^2). - вопрос №151201257412352103416545634 от serovau85 05.09.2021 23:08

Question

Математика: 1)f(x)= x^5 -1/x^2, x0=-1 2) y = 5x^7-(4/x)+(1/x^2). 3) f(x) = 5x^2 -10x^3. 4) f (x) 0. f(x) =9x - (x^3/3)

serovau85 · Answer

Уравнение касательной: y= f(x0) + f (x0)*(x-x0) f(x0) = f(1) = 1 + 5 - 3 = 3 f (x ) = 2x + 5 f (x0) = f (1) = 7 y = 3 + 7*(x-1) = 7x-4....

1)f(x)= x^5 -1/x^2, x0=-1 2) y = 5x^7-(4/x)+(1/x^2). 3) f(x) = 5x^2 -10x^3. 4) f'(x) > 0. f(x) =9x - (x^3/3)