1целая 31/32* 3 целых 1/5-(8 целых 5/9*6/35+2 целых - вопрос №1313231585963522155125621911 от kivonen3p08qoq 21.02.2022 16:22

Question

Математика: 1целая 31/32* 3 целых 1/5-(8 целых 5/9*6/35+2 целых 2/15)*5/12

kivonen3p08qoq · Answer

1 31/32 * 3 1/5-(8 5/9 * 6/35 + 2 2/15) * 5/12=

1) 8 5/9 * 6/35= 77/9 * 6/35 = 77*2/35*3 = 154/105= 1 49/105
2) 1 49/105 + 2 2/15 = 1 49/105 + 2 14/105 = 3 63/105
3) 1 31/32 * 3 1/5 = 63/32 * 16/5= 63/2*5 = 63/10= 6 3/10
4) 3 63/105 * 5/12= 378/105 * 5/12 = 63/21 * 1/2 = 3/2= 1 1/2
5) 6 3/10 - 1 1/2= 6 3/10 - 1 5/10= 5 13/10 - 1 5/10= 4 8/10= 4 4/5