(24+x)-21=10 (45-y)+18=58 (y-35)+12=32 56-(x+12)=24 - вопрос №2421104518583512325612245515306198395 от Gu1ya04 02.04.2021 13:06

Question

Математика: (24+x)-21=10 (45-y)+18=58 (y-35)+12=32 56-(x+12)=24 55-(x-15)=30

Gu1ya04 · Answer

(24+х)-21=1024+х=10+2124+х=31х=31-24х=7(45-у)+18=3245-у=32-1845-у=14у=45-14у=31(у-35)+12=32у-35=32-12у-35=20у=20+35у=5556-(х+12)=24х+12=56-24х+12=32х=32-12х=2055-(х-15)=30х-15=55-30х-15=25х=25+15х=40...