-3/11*(-2/15)*7целых и 1/3*на (-6)*40= -5*(-4)*(-3)*(-1)*(1/3*1/4*1/5)=(9, - вопрос №3112157136405431131415930281417007784 от qwerty999999fgh 02.07.2022 14:27

Question

Математика: -3/11*(-2/15)*7целых и 1/3*на (-6)*40= -5*(-4)*(-3)*(-1)*(1/3*1/4*1/5)=(9, 3-0, 28*(-1/4))*(-72, 59)=Решите до 18:50 ​

qwerty999999fgh · Answer

1) (1/4 - 2/3)*(4/5 - 2/15)*(-3/5)=-5/12*10/15*(-3/5)=1/62) (1/6 - 5/9)*(1/2 - 3/7)*7целых 1/5=-7/18*1/14*36/5=-1/53) (5/6 - 2/3)*(7/8 - 1/2)*(-4)=1/6*3/8*(-4)=-1/4...

-3/11*(-2/15)*7целых и 1/3*на (-6)*40= -5*(-4)*(-3)*(-1)*(1/3*1/4*1/5)=(9, 3-0, 28*(-1/4))*(-72, 59)=Решите до 18:50 ​

-3/11(-2/15)7целых и 1/3на (-6)40= -5(-4)(-3)(-1)(1/31/41/5)=
(9, 3-0, 28(-1/4))(-72, 59)=
Решите до 18:50