(3 целых 3/4*3/4-8 целых 4/9: 3 целых 4/5+1 целая - вопрос №334348493451122713948308422592 от ayzhan1979 31.05.2023 22:35

Question

Математика: (3 целых 3/4*3/4-8 целых 4/9: 3 целых 4/5+1 целая 1/2: 27): 1 целая 39/48 по действием 30 !

ayzhan1979 · Answer

(3 3/4*3/4 - 8 4/9 : 3 4/5 + 1 1/2 : 27) : 1 39/48

1) 3 3/4 * 3/4 = 15/4 * 3/4 = 45/16

2) 8 4/9 : 3 4/5 = 76/9 : 19/5 = 76/9 * 5/19 = 20/9

3) 1 1/2 : 27 = 3/2 : 27/1 = 3/2 * 1/27 = 1/18

4) 45/16 -20/9 + 1/18 = 45*9*18/2592 - 20*16*18/2592 + 1*9*16/2592 =

7290/2592 - 5760/2592 +144/2592 = 1674/2592 = 93/144

5) 93/144 : 1 39/48 = 93/144 : 87/48 = 93/144 * 48/87 = 31/3 * 1/29 = 31/87