41/3 : (5/6 +0,25 ) и вот еще 3,6 •( 7/12 +1/9) - вопрос №4135602536712195917670 от skabshkqbsianshj 27.09.2021 10:41

Question

Математика: 41/3 : (5/6 +0,25 ) и вот еще 3,6 •( 7/12 +1/9)

skabshkqbsianshj · Answer

решить пример 4 целых 1/3 * (5/6+0.25)*3,6*(7/12+1/9)*(7/12-2/15) разделить 0,9*(5/8-1/3)*1целая5/7

4_1/3 * (5/6+0.25)*3,6*(7/12+1/9)*(7/12-2/15) /(0,9*(5/8-1/3)*1_5/7)=
=(13/3) * (5/6+0.25)*3,6*(7/12+1/9)*(7/12-2/15) /(0,9*(5/8-1/3)*(12/7))=
(13/3) * (5/6+1/4)*(18/5)*(7/12+1/9)*(7/12-2/15) /(0,9*(5/8-1/3)*(12/7))=
=(13/3) * (13/12)*(18/5)*(25/36)*(27/60) /(0,9*(7/2)*(1/7))=
=13*(13/4)*(1/4)*(1/2) /((9/10)*(7/2)*(1/7))=
=((13*13*1*1)/(4*4*2)) /((9*7*1)/(10*2*7))=
=(169/32) /(63/140)=
=(169*140)/(32*63)=
=(169*35)/(8*63)=
=(169*5)/(8*9)=
=845/72 = 11_53/72 (11 целых и 53/72)
Если задание выглядит так:
(4_1/3)/(5/6+0.25)*3,6*(7/12+1/9)*(7/12-2/15) /(0,9*(5/8-1/3)*1_5/7)=
=(13/3)/(5/6+0.25)*3,6*(7/12+1/9)*(7/12-2/15) /(0,9*(5/8-1/3)*(12/7))= 10