A)sin43cos13-sin47cos77 б)sin34cos11+sin56cos79 в) - вопрос №43134777341156791733134 от kashaavablogHhfjdk 07.07.2020 13:10

Question

Математика: A)sin43cos13-sin47cos77 б)sin34cos11+sin56cos79 в) г) д)

kashaavablogHhfjdk · Answer

Sin43cos13-sin(90-43)cos(90-13)=sin43cos13-cos43sin13=sin(43-13)=sin30=1/2
sin34cos11+sin(90-34)cos(90-11)=sin34cos11+cos34sin11=sin(34+11)=sqrt(2)/2
(sinacos3a+sin3acosa)/sinacosa=sin4a/1/2sin2a=2sin4a/sin2a=4cos2a
sina/cosa+cosa/sina=1/sinacosa=2/sin2a
sinП/7cosП/7cos2П/7cos4П/7/sinП/7=1/8sin8П/7/sinп/7=1/8(sin(П+П/7)/sinП/7)=-1/8