Как находить растояние на карте в ? надо

b)

3-3cosx=2(< var > 2cos^{2}(x) < /var ><var>2cos

2

(x)</var> -1)

4< var > cos^{2}(x)+3*cos(x)-5=0 < /var ><var>cos

2

(x)+3∗cos(x)−5=0</var> cos(x)=t,-1<t<1

4t^2+3t-5=0

D=9+80=89

< var > \sqrt{D}=89\approx=9.4 < /var ><var>

D

=89≈=9.4</var>

< var > x_1=(-3-9.4)/8=-5/8 < /var ><var>x

1

=(−3−9.4)/8=−5/8</var>

< var > x_2=(-3+9,4)/8=0.8 < /var ><var>x

2

=(−3+9,4)/8=0.8</var>

Обратная замена

cosx=-5/8 cosx=0.8

x=+-arccos(-5/8)+2< var > \pi < /var ><var>π</var> *n x=+-arccos(0.8)+2< var > \pi < /var ><var>π</var> *n

Пошаговое объяснение:

7x = -30 + 2x

7x - 2x = 30

5x = 30

x = 30:5

x = 6

16 - 18x = -25x - 12

25x - 18x = -12 - 16

7x = -28

x = -28 : 7

x = -4

-17x + 20 = 7x - 28

7x + 17x = 20 + 28

24x = 48

x = 48:24

x = 2

20 - 2x = 27 + x

x + 2x = 20 - 27

3x = -7

x = -7 : 3

x = -2 1/3

0,2x + 4,3 = 0,4x - 6,5

0,4x - 0,2x = 4,3 + 6,5

0,2x = 10,8

x = 10,8 : 0,2

x = 54

0,6x + 100 = 0,9x + 1

0,9x - 0,6x = 100 - 1

0,3x = 99

x = 99:0,3

x = 330

-9/14 x + 18 = -2/3 x + 17

-9/14 x + 2/3 x = 17 - 18

-27/42 x + 28/42 x = -1

1/42 x = -1

x = -1 * 42/1

x = -42

-8/15 x - 11 = 4/9 x + 11

-8/15 x - 4/9 x = 11 + 11

-24/45 x - 20/45 x = 22

-44/45 x = 22

x = 22 * (-45/44)

x = -45/2

x = -22 1/2