Как сделать скажите ! [tex](5 rac{3}{7} - 3 - вопрос №537325311735410106799 от nastiaUA 05.02.2022 15:54

Question

Математика: Как сделать скажите ! [tex](5 rac{3}{7} - 3 rac{2}{5}) + (3 - 1 rac{17}{35}) - (4 - rac{12}{15} - 3 rac{19}{105})[/tex][tex](7 rac{7}{9} - 5 rac{1}{3}) - (2 - 1 rac{5}{6}) + (9 rac{19}{36} - 3 rac{11}{12}) [/tex]​

nastiaUA · Answer

(5 3/7 - 3 2/5) + (3 - 1 17/35) - (4 - 12/15 - 3 19/105) = 3 целых 11/21.

1) 5 3/7 - 3 2/5 = 5 15/35 - 3 14/35 = 2 1/35

2) 3 - 1 17/35 = 2 35/35 - 1 17/35 = 1 18/35

3) 4 - 12/15 = 3 15/15 - 12/15 = 3 3/15 = 3 1/5

4) 3 1/5 - 3 19/105 = 3 21/105 - 3 19/105 = 2/105

5) 2 1/35 + 1 18/35 = 3 19/35

6) 3 19/35 - 2/105 = 3 57/105 - 2/105 = 3 55/105 = 3 11/21

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(7 7/9 - 5 1/3) - (2 - 1 5/6) + (9 19/36 - 3 11/12) = 7 целых 8/9.

1) 7 7/9 - 5 1/3 = 7 7/9 - 5 3/9 = 2 4/9

2) 2 - 1 5/6 = 1 6/6 - 1 5/6 = 1/6

3) 9 19/36 - 3 11/12 = 9 19/36 - 3 33/36 = 8 55/36 - 3 33/36 = 5 22/36 = 5 11/18

4) 2 4/9 - 1/6 = 2 8/18 - 3/18 = 2 5/18

5) 2 5/18 + 5 11/18 = 7 16/18 = 7 8/9

Как сделать скажите ! ​

Как сделать скажите !
$(5 \frac{3}{7} - 3 \frac{2}{5}) + (3 - 1 \frac{17}{35}) - (4 - \frac{12}{15} - 3 \frac{19}{105})$
$(7 \frac{7}{9} - 5 \frac{1}{3}) - (2 - 1 \frac{5}{6}) + (9 \frac{19}{36} - 3 \frac{11}{12})$