Log1/2(x+y)=-3 log3(x+2y)=1 системы: 2^x-2^y=28 x+y=7 - вопрос №123321222877074614 от valeriacom11 30.06.2022 03:41

Question

Математика: Log1/2(x+y)=-3 log3(x+2y)=1 системы: 2^x-2^y=28 x+y=7

valeriacom11 · Answer

Logxy+2logyx=3x+y=26logxy=1/logyx 1/logyx+2logyx=3 t=logyx 1/t+2t-3=0 t 0 1+2t^2-3t=0 d=9-8=1 t=3-1/4=1/2 t2=3+1/4=1 logyx=1/2 x=y^1/2=vy logyx=1 x=yx1=vy = x+y=26 vy+y=26 y+vy-26=0 d=1+104=105 vd=v105 y=-1+v105/2 x=26-(v105-1)/2x2=y 2y=26 y=13 x=13...