1) f(-3) = 243 - 432 + 2 = 677
2) f(1) = 3 - 16 + 2 = -11
3) f'(x) = 12x^3 - 48x^2
4) f'(x) = 0
12x^3 - 48x^2 = 0
12x^2 (x - 4) = 0
x = 0, x = 4
{[x = 0
{[x = 4 x = 0
{ x € [-3 ; 1]
5) f(0) = 2
max f(x) = f(-3) = 677
[-3 ; 1]
min f(x) = f(1) = -11
ответ : -11, 677
1) f(-3) = 243 - 432 + 2 = 677
2) f(1) = 3 - 16 + 2 = -11
3) f'(x) = 12x^3 - 48x^2
4) f'(x) = 0
12x^3 - 48x^2 = 0
12x^2 (x - 4) = 0
x = 0, x = 4
{[x = 0
{[x = 4 x = 0
{ x € [-3 ; 1]
5) f(0) = 2
max f(x) = f(-3) = 677
[-3 ; 1]
min f(x) = f(1) = -11
[-3 ; 1]
ответ : -11, 677