sin〖π/4〗 cos〖π/4〗-sin〖π/3〗 cos〖π/6〗=√2/2*√2/2-√3/2*√3/2=2/4-3/4=-1/4
(tg〖π/4〗-ctg π/3)(ctg π/4+tg〖π/6〗 )=(1-1/√3)*(1+1/√3)=1^2-(1/√3)^2=1-1/3=2/3
Пошаговое объяснение:
sin〖π/4〗 cos〖π/4〗-sin〖π/3〗 cos〖π/6〗=√2/2*√2/2-√3/2*√3/2=2/4-3/4=-1/4
(tg〖π/4〗-ctg π/3)(ctg π/4+tg〖π/6〗 )=(1-1/√3)*(1+1/√3)=1^2-(1/√3)^2=1-1/3=2/3
Пошаговое объяснение: