2cos(2x + π/4) = – √2
2(cos2x cosπ/4 -sin2x sinπ/4 ))-√2
2(cos2x*√2/2 - sin2x*√2/2)-√2
2(√2cos2x/2 - √2sin2x/2)-√2
2*√2cos2x - √2sin2x/2 - √2
√2cos2x - √2sin2x - √2
ответ: √2cos2x - √2sin2x - √2
2cos(2x + π/4) = – √2
2(cos2x cosπ/4 -sin2x sinπ/4 ))-√2
2(cos2x*√2/2 - sin2x*√2/2)-√2
2(√2cos2x/2 - √2sin2x/2)-√2
2*√2cos2x - √2sin2x/2 - √2
√2cos2x - √2sin2x - √2
ответ: √2cos2x - √2sin2x - √2