Решите, , неравенства: 2sin(2x/3) =-1 2cos(3п-x/4)+3sin(п/2-x/4) - вопрос №223123432402801327 от GRISHINANASTYA 12.09.2021 18:43

Question

Математика: Решите, , неравенства: 2sin(2x/3) =-1 2cos(3п-x/4)+3sin(п/2-x/4) 0

GRISHINANASTYA · Answer

2sin(2x/3) ≤ -1sin(2x/3) ≤ -1/24π/3 + 2πn ≤ 2x/3 ≤ 5π/3 + 2πn, n∈Z |*3/2 2π+2πn ≤ x ≤ 2,5π+2πn, n∈Z[2π+2πn ; 2,5π+2πn] , n∈Z2cos(3π-x/4)+3sin(π/2-x/4) 0-2cos x/4 + 3cos x/4 0cos x/4 0π/2 + 2πn x/4 3π/2 + 2πn, n∈Z |*42π+4πn x 3π + 4πn, n∈Z(2π+4πn; 3π + 4πn), n∈Z...

Решите, , неравенства: 2sin(2x/3)< =-1 2cos(3п-x/4)+3sin(п/2-x/4)< 0