Решите: sin6x * cos6x = -1/2; sinx + sin3x = 0; sin3x - вопрос №6612303706585093 от 559858 01.11.2020 15:59

Question

Математика: Решите: sin6x * cos6x = -1/2; sinx + sin3x = 0; sin3x - sin7x = 0.

559858 · Answer

1)sin6x*cos6x=-1/2|*22sin6xcos6x=-1sin12x=-112x=-п/2+2пn,n€zx=-п/24+пn/6,n€z2)sinx+sin3x=02sin(x+3x/2)cos(x-3x/2)=02sin2xcosx=0|:2sin2xcosx=0sin2x=02x=пn,n€zx=пn/2,n€zcosx=0x=п/2+пn,n€z3)sin3x-sin7x=02sin(3x-7x/2)cos(3x+7x/2)=0-2sin2xcos5x=0 |:(-2)sin2xcos5x=0sin2x=02x=пn,n€zx=пn/2,n€zcos5x=05x=п/2+пn,n€zx=п/10+пn/5,n€z...