{(х+у)^2=2у
{(х+у)^2=2х
x, y ≥ 0
2x = 2y
x = y
(x + x)² = 2x
4x² = 2x
x(2x - 1) = 0
x = 0 y = 0
x = 1/2 y = 1/2
ответ (0,0) (1/2,1/2)
{(х+у)^2=2у
{(х+у)^2=2х
x, y ≥ 0
2x = 2y
x = y
(x + x)² = 2x
4x² = 2x
x(2x - 1) = 0
x = 0 y = 0
x = 1/2 y = 1/2
ответ (0,0) (1/2,1/2)