(2 - x)*(2x + 1) = (x - 2)*(x + 2)
4х+2-2х²-x=x²+2x-2x-4
-2x²+3x+2-x²+4=0
-3x²+3x+6=0 |: -3
x²-х-2=0
D=b²-4ac= (-1)²-4*1*(-2)=1+8=9
x= -b±√D /2а
x=1+√9 /2*1=(1+3):2=4:2=2
х=1- √9 /2*1=(1-3):2= -2:2= -1
х1=2; х2= -1
(2 - x)*(2x + 1) = (x - 2)*(x + 2)
4х+2-2х²-x=x²+2x-2x-4
-2x²+3x+2-x²+4=0
-3x²+3x+6=0 |: -3
x²-х-2=0
D=b²-4ac= (-1)²-4*1*(-2)=1+8=9
x= -b±√D /2а
x=1+√9 /2*1=(1+3):2=4:2=2
х=1- √9 /2*1=(1-3):2= -2:2= -1
х1=2; х2= -1