Теңдеулер жүйесінің шешімін қосу тәсілімен табыңдар:
1) (2(x+ Зу) + 9 =х+6,
3) (4 (3х +y) - 1= y – 2х,
|3(х – 2y) = х + 30;
2 (4x - у) + 19 = -х;
2) (5(3х + 2) = 7+ 12у.
4) (2(x+2y) – 7y = 6,
4(x + y) +1 = 31;
5(2x + y)-x = 2x + 60​

2(х+3у)+9=х+6

  3(х-2у)=х+30 

2x+6y+9=x+6

3x-6y=x+30

x+6y+3=0

2x-6y-30=0 

3x-27=0

3x=27

x=9

9+6y+3=0

6y=-12

y=-2

(9;-2)

2) 5(3х+2)=7+12у

4(х+у)+х=31

15x+10=7+12y

4x+4y+x=31

15x-12y=-3

5x+4y=31 |*3

15x-12y=-3

15x+12y=93

30x=90

x=3

45+12y=93

12y=48

y=4

(3;4)

3)4(3х+у)-1=у-2х

2(4х-у)+19=-х

12x+4y-1=y-2x

8x-2y+19=-x

14x+3y=1     | *2

9x-2y+19=0 |*3

28x+6y=2

27x-6y=-57

55x=-55

x=-1

-14+3y=1

3y=15

y=5

(-1;5)

4) 2(х+2у)-7у=6

5(2х+у)-х=2у+60

2x+4y-7y=6

10x+5y-x=2y+60

2x-3y=6

9x+3y=60

11x=66

x=6

12-3y=6

-3y=-6

y=2

(6;2)