Tg(3x-π/6)-√3=0
решить уравнение​

tg(3x - π/6) - √3 = 0

tg(3x - π/6) = √3

3x - π/6 = π/3 + πk, k ∈ ℤ

3x = π/3 - π/6 + πk, k ∈ ℤ

3x = π/6 + πk, k ∈ ℤ / : 3

x = π/18 + πk/3, k ∈ ℤ

• Формула:

tg(x) = b

x = arctg(b) + πk, k ∈ ℤ

ответ: x = π/18 + πk/3, k ∈ ℤ