точка P является серединой ребра bb1 куба ABCD A1 B1 C1 D1. Длина ребра куба равна 4. Плоскость альфа проходит через точку D1 параллельно прямой C1P и альфа паралельна AC. Постройте сечение этого Куба плоскостью Альфа и найдите площадь этого сечения
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Пошаговое объяснение:
лва а аьвre4th is the first of many of our clients and family to the first of many of our friends and family to the first of many of our friends and family to the first of many of our friends and family to the first of many of our friends and family to the first of many of our friends and family to the first of many of our friends and family to the first of many of our friends and family to the first of many of our friends and family to the first of many of our friends and family to the first of many of our friends and family to the first of many of our friends and family to the first of many of our friends and
ответ
1)13x-6x=-4-10
7x=-14
x=-2
2)х+4х+х-3=75
6х-3=75
6х=75+3
6х=78
х=78:6
х=13 кг в первом ящике
4*13=52 кг во втором ящике
13-3=10 кг в третьем ящике
3)0,4x-1,2+2,5=2+0,5x
0,4x+1,3=2+0,5x
0,4x-0,5x=2-1,3
-0,1x=0,7
x=0,7:(-0,1)
x=-7
4)Пусть у Пети осталось х р.
Пусть у Васи осталось 5х р.
х + 400 = 5х + 200
х=50
400+50=450 р. было у Пети
200+5*50=200+250=450 р. было у Васи
ответ: У них было ненег поровну, то есть по 450 р.
5) (4y+6)(1.8-0.2y)=0
7.2y-0.8y^2+10.8-1.2y=0
-0.8y^2+6y+10.8=0
D=36-4*(-0.8)*10.8=70.56
y1=(-6+8.4)/(-1.6)=-1.5
y2=(-6-8.4)/(-1.6)=9
Удачи
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