У Анара есть 60 тг тремя монетами по 20 тг.Она хочеть купить яблока 20 тг,груша 20 тг и вишня 10 тг.Как Анар можеть разменять деньги,чтобы дать продавцу деньги без сдачи монетами по 20 тг.

1337) 12/24 16/24 18/24 4/24 9/24 10/24

1335) 4/5 3/5 6/7 2/3 5/8

1339) (6 1/4-4 1/8)*4+3 1/3:2 1/2 =9 5/6

1) 1/4-4 1/8=2 1/4-1/8=2 2/8-1/8=2 1/8

2) 1/8·4=17/8·4=17/2=8 1/2

3) 1/3:2 1/2= 10/3:5/2=10/3·2/5=4/3

4)8 1/2+1 1/3=9 3/6+ 2/6=9 5/6

(2 4/9+1 1/6)×1 4/5 -3 1/9÷ 2 1/3

1)2 4/9+1 1/6=2 8/18+1 3/18=3 11/18

2)3 11/18*1 4/5=13/2=6 1/2

3)3 1/9:2 1/3=28/9:7/3=4/3=1 1/3

4)6 1/2-1 1/3=6 3/6-1 2/6=5 1/6

(2-1 7/12)/(3 / 8 - 1 /6)* 3 1/4

1)2-1 7/12=1 12/12-1 7/12=5/12

2)3/8-1/6= 9-4/24=5/12

3)5/12:5/24=5/12*24/5=2

4)2/1*3 1/4=2/1*13/4=13/2=6 1/2

(7/10-2/5)*(1/4+5/6):6 1/2

1) 7/10-2/5=(7-4)/10=3/10

2) 1/4+5/6= (3+10)/12=13/12

3) 3/10*13/12:13/2=1/20

Пошаговое объяснение:

Хм, интересное задание.

Кол-во символов в строке = 24

Кол-во букв "a" на английской раскладке = 8

Кол-во букв "s" = 8

Кол-во букв "d" = 8

"a" = "s" = "d"

"a" + "a" = 16

"a" + "s" = "s" + "a" = 16

"a" + "d" = "d" + "a" = 16

"s" + "s" = 16

"s" + "d" = "d" + "s" = 16

"d" + "d" = 16

"a" - "a" = 0

"a" - "s" = "s" - "a" = 0

"a" - "d" = "d" - "a" = 0

"s" - "s" = 0

"s" - "d" = "d" - "s" = 0

"d" - "d" = 0

"a" : "a" = 1

"a" : "s" = "s" : "a" = 1

"a" : "d" = "d" : "a" = 1

"s" : "s" = 1

"s" : "d" = "d" : "s" = 1

"d" : "d" = 1

"a" × "a" = 64

"a" × "s" = "s" × "a" = 64

"a" × "d" = "d" × "a" = 64

"s" × "s" = 64

"s" × "d" = "d" × "s" = 64

"d" × "d" = 64

Это задание было сложно понять. Фух...